Questions are in black, answers in blue.
Well, your argument about real numbers isn't convincing because once you're narrowed it down enough that you have a single vertex of the original feasible region, you can calculate the coordinates of that vertex as precisely as you like.
Don't be. If k is a constant and n is equal to k, then the running time is constant with respect to n. We are interested in the running time function as n increases, for each constant value of k.
Sure. In the decision problem, the input is the constraint
list (both inequality and equality constraints) and the answer is the boolean
saying "feasible" or "not feasible". You are not told about any particularly
vector in the feasible region, but you can trust that one exists if the answer
is "feasible".
In the optimization problem the input
is the constraints and a cost function, and the output is either a vector that
achieves the optimal value of the cost function, a statement that the cost
function is unbounded, or a statement that the feasible region is empty.
Thus one of your two reductions is trivial.
No, it isn't, sorry. Let's put linear time as a condition of the problem. For the adjustment to the random coloring that I have in mind, you can make a single pass over the edge list in only linear time.
Yes, of course -- if A and B are decision problems and A Karp-reduces to B, it is immediate that A also Cook-reduces to B. If you have a poly-time decider for B, and f is a function Karp-reducing A to B, you can decide whether x is in A in poly time by computing f(x) and running the B-decider on it.
Congratulations, you appear to have found an
as-yet-unreported error in CLRS, from whence I took this problem.
(It's 35-2 on page 1050, not 35-4 as I originally said.) I have modified
the problem so that you are only asked for a PTAS, and I will report the
mistake to them.
It is true that if MAX-CLIQUE has a constant-factor approximation
scheme, then there is an FPTAS, because by the PCP Theorem the existence of
a PTAS implies P = NP. But I explicitly asked you not to use this result
in your proof.
You're quite right, I'll rename one of the variables.
Last modified 12 December 2005